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Unrolling a Cylinder

Part of the Surface Area & Volume section of Coddy's Geometry journey. Lesson 36 of 60.

Peel the label off a can and lay it flat: it is a rectangle. Its height is the can's height, and its width is the distance round the can, the circumference 2⋅π⋅r2\cdot \pi\cdot r. So the curved side has area 2⋅π⋅r⋅h2\cdot \pi\cdot r\cdot h. Add the two circle ends, π⋅r2\pi\cdot {r}^{2} each.

A cylinder with radius 2 and height 5

This cylinder has radius 2 and height 5. The ends make 2⋅π⋅22=8⋅π2\cdot \pi\cdot {2}^{2} = 8\cdot \pi, the curved side makes 2⋅π⋅2⋅5=20⋅π2\cdot \pi\cdot 2\cdot 5 = 20\cdot \pi, and the total is 28π.

The rule is Surface area of a cylinder: SA=2⋅π⋅r2+2⋅π⋅r⋅hSA = 2\cdot \pi\cdot {r}^{2}+2\cdot \pi\cdot r\cdot h. An open pipe would have only the curved part, and a cup only one end: read what the question covers.

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Challenge

Find the exact surface area of the cylinder, ends included: tap the solid, pick the rule, then press Check.

Try it yourself

Find the marked part of the figure

Find the marked part of the figure

All lessons in Surface Area & Volume