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Domain of a Root

Part of the Radicals & Rational Exponents section of Coddy's Algebra 2 journey. Lesson 32 of 40.

A radical function has its input under a root, like f(x)=2x−10f\left(x\right) = \sqrt{2x-10}. Some inputs break it. With input 1 the inside is 2−102-10, which is -8, and no real number squares to a negative. The domain is every input the rule accepts.

To find it, ask for the inside to be at least 0: 2x−10≥02x-10 \ge 0. Move the -10 across to get 2x≥102x \ge 10, then divide by 2: x≥5x \ge 5. The input 5 itself is allowed, since the square root of 0 is 0.

A cube root has no such limit. cbrt(−8)cbrt\left(-8\right) is -2, because -2 cubed is -8. So g(x)=cbrt(x−8)g\left(x\right) = cbrt\left(x-8\right) accepts every real input. Only an even root, like the square root, shuts out negatives.

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Challenge

Find the domain of f(x)=3x−12f\left(x\right) = \sqrt{3x-12}. The board holds the condition its inside must meet: solve it for x.

Try it yourself

3x−12≥03x-12 \ge 0

Get xx alone on one side

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