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One Root Below

Part of the Radicals & Rational Exponents section of Coddy's Algebra 2 journey. Lesson 13 of 40.

Look at 63\frac{6}{\sqrt{3}}. It is a perfectly good number, but to estimate it you would have to divide 6 by 1.732 by hand. So there is an agreement: keep roots out of the bottom of a fraction. Rewriting a fraction so its bottom has no root is called rationalizing the denominator, because the bottom becomes a rational number.

The tool is a fact from the last chapter: a root times itself is what was under it, 3⋅3=3\sqrt{3}\cdot \sqrt{3} = 3. Multiply the top and the bottom by 3\sqrt{3}. That is multiplying by 33\frac{\sqrt{3}}{\sqrt{3}}, which is 1, so the value does not change:

63=633⋅3=633\frac{6}{\sqrt{3}} = \frac{6\sqrt{3}}{\sqrt{3}\cdot \sqrt{3}} = \frac{6\sqrt{3}}{3}

Now cancel the 3 into the 6, and the answer is 232\sqrt{3}. Why bother? A whole-number bottom is easier to work with: 22\frac{\sqrt{2}}{2} is half of 1.414, which you can do in your head, while 12\frac{1}{\sqrt{2}} is the same number but asks you to divide by 1.414. One agreed form also makes answers easy to compare: 55\frac{5}{\sqrt{5}} and 5\sqrt{5} look different, and rationalizing shows they are equal.

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Challenge

Write 105\frac{10}{\sqrt{5}} with no root in the denominator, then simplify it. Use the move chips.

Try it yourself

105\frac{10}{\sqrt{5}}

Clear the root from the denominator

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