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Exponent Rules Still Work

Part of the Radicals & Rational Exponents section of Coddy's Algebra 2 journey. Lesson 20 of 40.

The rules you learned for whole-number exponents hold for fractions too, as long as the base is positive. Multiplying powers of the same base adds the exponents: x13⋅x23=x13+23=x1{x}^{\frac{1}{3}}\cdot {x}^{\frac{2}{3}} = {x}^{\frac{1}{3}+\frac{2}{3}} = {x}^{1}, which is just x.

This agrees with what the powers mean. x13{x}^{\frac{1}{3}} is the cube root of x, so three of them multiplied should give x back: x13⋅x13⋅x13=x33{x}^{\frac{1}{3}}\cdot {x}^{\frac{1}{3}}\cdot {x}^{\frac{1}{3}} = {x}^{\frac{3}{3}}, which is x. In the same way x⋅x=x12+12\sqrt{x}\cdot \sqrt{x} = {x}^{\frac{1}{2}+\frac{1}{2}}, which is x.

The other rules carry over the same way. Dividing subtracts exponents, x54x14=x44\frac{{x}^{\frac{5}{4}}}{{x}^{\frac{1}{4}}} = {x}^{\frac{4}{4}}, and a power of a power multiplies them, (x13)9=x3{\left({x}^{\frac{1}{3}}\right)}^{9} = {x}^{3}. Add or subtract the fractions over a common denominator, then simplify: an exponent of 4/4 is 1.

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Challenge

Simplify x12⋅x32{x}^{\frac{1}{2}}\cdot {x}^{\frac{3}{2}}. Type each line in the box under the problem and press Enter: first a single power with the exponents added, then its simplest form.

Try it yourself

x12x32x^{\frac{1}{2}}x^{\frac{3}{2}}

Simplify

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