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Negative Exponents

Part of the Radicals & Rational Exponents section of Coddy's Algebra 2 journey. Lesson 19 of 40.

A negative exponent means one over, just as it did with whole numbers: 5−2=152=125{5}^{-2} = \frac{1}{{5}^{2}} = \frac{1}{25}. The minus in the exponent does not flip the sign of the answer. It moves the power below the line. One over a fraction turns it upside down, so a fraction base flips: 25−2=522=254{\frac{2}{5}}^{-2} = {\frac{5}{2}}^{2} = \frac{25}{4}.

With a fraction exponent, deal with the minus first, then the fraction as in the last lesson. Take 25−32{25}^{\frac{-3}{2}}:

25−32=12532=1(2512)3=153=1125{25}^{\frac{-3}{2}} = \frac{1}{{25}^{\frac{3}{2}}} = \frac{1}{{\left({25}^{\frac{1}{2}}\right)}^{3}} = \frac{1}{{5}^{3}} = \frac{1}{125}

Why one over? Multiply 2532{25}^{\frac{3}{2}} by 25−32{25}^{\frac{-3}{2}} and the exponents add to 0, and 250=1{25}^{0} = 1. Two numbers whose product is 1 are each other's reciprocals, so 25−32{25}^{\frac{-3}{2}} must be one over 2532{25}^{\frac{3}{2}}.

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Challenge

Work out 8−23{8}^{\frac{-2}{3}}. Type each line in the box under the problem and press Enter: move the power below the line, write its root and power as two steps, then finish the value.

Try it yourself

8−238^{\frac{-2}{3}}

Simplify

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