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Two Brackets

Part of the Radicals & Rational Exponents section of Coddy's Algebra 2 journey. Lesson 10 of 40.

Two brackets multiply the way they always have: every term in the first times every term in the second. Take (3+2)(1+2)\left(3+\sqrt{2}\right)\left(1+\sqrt{2}\right). That gives four products: 3 times 1, 3 times 2\sqrt{2}, 2\sqrt{2} times 1, and 2\sqrt{2} times 2\sqrt{2}.

3+32+2+23+3\sqrt{2}+\sqrt{2}+2

The last product is 2, because a root times itself is what is under it. Now collect: the numbers 3 and 2 make 5, and the roots make 424\sqrt{2}. The answer is 5+425+4\sqrt{2}.

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Challenge

Expand and simplify (2+3)(1+3)\left(2+\sqrt{3}\right)\left(1+\sqrt{3}\right).

Try it yourself

(2+3)(1+3)\left(2+\sqrt{3}\right)\left(1+\sqrt{3}\right)

Write it in simplest radical form

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