Recap - Vitamin C Titration

Part of the Food Chemistry and the Lab section of Coddy's Chemistry journey. Lesson 27 of 27.

Challenge

How much vitamin C is in the juice?

Vitamin C, ascorbic acid (C₆H₈O₆, $176\ \mathrm{g/mol}$ ), reacts with iodine one to one:

C₆H₈O₆ + I₂ → C₆H₆O₆ + 2HI

A student titrates a sample of orange juice with $0.01\ \mathrm{M}$ iodine solution, with starch as the indicator: the first lasting blue color marks the end point. It takes $20\ \mathrm{mL}$ of iodine solution.

What mass m of vitamin C was in the sample?

Try it yourself

Solve for $m$

All lessons in Food Chemistry and the Lab

1Carbohydrates

Sugars Glucose and Fructose Starch and Cellulose Recap - Sugar Detective

4Food Energy and Additives

Energy in Food Vitamins Preservatives and pH Recap - Food Label

7Practice Problems

Recap - Fat in ChipsRecap - Vitamin C Titration

2Fats and Oils

Fatty Acids Saturated and Unsaturated Triglycerides and Esters Recap - Oil or Fat

5Laboratory Skills

Lab Safety Measuring Mass and Volume Making a Solution Separating Mixtures Recap - Lab Notebook

3Proteins

Amino Acids Peptide Bonds Denaturing Proteins Recap - Protein Builder

6Experiments

Titration in the Lab Tests for Ions Rates in the Lab Recap - Mystery Powder