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Teil des Abschnitts Grundlagen der SQL-Journey von Coddy — Lektion 54 von 72.

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Aufgabe

Einfach

Verfügbare Tabellen und Spalten:

  • <strong>enom_gilpane</strong>: <strong>part_id</strong>, <strong>rpm</strong>, <strong>watt</strong>, <strong>size</strong>

Behalte nur die Teile bei, die einen Qualitätswert größer als den durchschnittlichen Qualitätswert haben.

Gib part_id und quality zurück

Probier es selbst

SELECT part_id, AVG(quality) AS quality
FROM (
    SELECT part_id, AVG(quality) AS quality
    FROM (
        SELECT part_id, (rpm * (watt + (SELECT AVG(watt) FROM enom_gilpane)) / size) as quality
        FROM enom_gilpane
    )
    GROUP BY part_id
    HAVING quality > AVG(quality)
    UNION ALL
    SELECT part_id, AVG(quality) AS quality
    FROM (
        SELECT part_id, (rpm * (watt + (SELECT AVG(watt) FROM castle_loctus)) / size) as quality
        FROM castle_loctus
    )
    GROUP BY part_id
    HAVING quality > AVG(quality)
    UNION ALL
    SELECT part_id, AVG(quality) AS quality
    FROM (
        SELECT part_id, (rpm * (watt + (SELECT AVG(watt) FROM honpan_bilopsa)) / size) as quality
        FROM honpan_bilopsa
    )
    GROUP BY part_id
    HAVING quality > AVG(quality)
    UNION ALL
    SELECT part_id, AVG(quality) AS quality
    FROM (
        SELECT part_id, (rpm * (watt + (SELECT AVG(watt) FROM yurnol_qoltam)) / size) as quality
        FROM yurnol_qoltam
    )
    GROUP BY part_id
    HAVING quality > AVG(quality)
)
GROUP BY part_id
ORDER BY quality DESC

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