A Circle and a Line
Part of the Quadratics & Complex Numbers section of Coddy's Algebra 2 journey. Lesson 40 of 51.
The same method works for curves that are not parabolas. Take x^2 + y^2 = 25. By Pythagoras, a point (x, y) is at distance 5 from the origin exactly when this equation holds, so its graph is the circle of radius 5 centred at (0, 0). The number on the right is the radius squared.
To meet it with the line y = x + 1, substitute the line into the circle: x^2 + (x + 1)^2 = 25. Expand the bracket, x^2 + x^2 + 2x + 1 = 25, then collect and move the 25: 2x^2 + 2x - 24 = 0. Divide by 2 and factor: (x + 4)(x - 3) = 0, so x is -4 or 3.
Find each y from the line: x = 3 gives y = 4, and x = -4 gives y = -3. The meeting points are (3, 4) and (-4, -3), and both check in the circle, since 9 + 16 and 16 + 9 are 25. Substitute into the circle, not the other way round: only the line says what y is.
Challenge
The circle x^2 + y^2 = 10 and the line y = x + 2 meet in two points. Find both.
Try it yourself
Solve for x,y
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Quadratics & Complex Numbers
2Completing the Square
Perfect Square TrinomialsThe Missing NumberCompleting the SquareIrrational AnswersWhen a Is Not 1Recap: Completing the Square5Complex Arithmetic
Adding and SubtractingMultiplyingThe ConjugateDividingA Pure Imaginary BottomRecap: Complex Arithmetic8Lines Meet Parabolas
Two CrossingsJust TouchingNo MeetingA Circle and a LineRecap: Lines and Parabolas