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Two Crossings

Part of the Quadratics & Complex Numbers section of Coddy's Algebra 2 journey. Lesson 34 of 48.

A line and a parabola can meet. The meeting points are the solutions of a system: pairs (x, y) that make both equations true at once. Take y=x2+1y = {x}^{2}+1 and y=3x−1y = 3x-1.

Both equations say what y is, so at a meeting point the two right sides are equal. Substitute one into the other: x2+1=3x−1{x}^{2}+1 = 3x-1, a quadratic in x alone. Move every term to one side, x2−3x+2=0{x}^{2}-3x+2 = 0, and factor: (x−1)(x−2)=0\left(x-1\right)\left(x-2\right) = 0, so x is 1 or 2.

Each x needs its own y. Put it into the line, the simpler equation: x = 1 gives y = 2, and x = 2 gives y = 5. The meeting points are (1, 2) and (2, 5). An answer is a pair, so an x without its y is only half of one.

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Challenge

Find every point where the parabola y=x2−3y = {x}^{2}-3 meets the line y=2xy = 2x. Give each answer as x and y.

Try it yourself

y=x2−3y = x^{2}-3y=2xy = 2x

Find xx, yy

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