A Pure Imaginary Bottom
Part of the Quadratics & Complex Numbers section of Coddy's Algebra 2 journey. Lesson 26 of 51.
When the bottom is only imaginary, like 2i, its real part is 0, so its conjugate is -2i. That works: (2i)(-2i) = -4i^2, which is 4, a real number.
Multiplying by i works too, with smaller numbers: (2i)(i) = 2i^2, which is -2. Any nonzero real multiple of i makes the bottom real.
Take (8 - 6i)/(2i). Times i on top and bottom: the top is 8i - 6i^2, which is 6 + 8i, and the bottom is -2. Split the fraction: 6 over -2 is -3, and 8i over -2 is -4i, so the answer is -3 - 4i. The bottom is negative, so every sign of the top flips.
Challenge
Divide (6 + 4i)/(2i) and write the answer as a + bi.
Try it yourself
Simplify the expression
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Quadratics & Complex Numbers
2Completing the Square
Perfect Square TrinomialsThe Missing NumberCompleting the SquareIrrational AnswersWhen a Is Not 1Recap: Completing the Square5Complex Arithmetic
Adding and SubtractingMultiplyingThe ConjugateDividingA Pure Imaginary BottomRecap: Complex Arithmetic8Lines Meet Parabolas
Two CrossingsJust TouchingNo MeetingA Circle and a LineRecap: Lines and Parabolas