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Fractions in the Answer

Part of the Quadratics & Complex Numbers section of Coddy's Algebra 2 journey. Lesson 31 of 51.

When a is not 1, the bottom of the formula, 2a, is no longer 2, and the parts often come out as fractions. Take 9x^2 + 6x + 5 = 0: a is 9, b is 6, c is 5, and b^2 - 4ac is 36 - 180, which is -144. Its root is 12i.

So x = (-6 ± 12i)/18. Divide each term of the top by 18 and reduce: -6 over 18 is -(1/3), and 12 over 18 is 2/3. The solutions are x = -(1/3) + (2/3)i and x = -(1/3) - (2/3)i.

Why divide term by term? The form a + bi names the real part and the imaginary part separately, so each gets its own fraction, reduced. A common slip is to reduce one term and forget the other.

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Challenge

Solve 4x^2 + 4x + 5 = 0 with the quadratic formula. Write each solution as a + bi.

Try it yourself

4x^2 + 4x + 5 = 0

Solve for x

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