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Three Kinds of Answers

Part of the Quadratics & Complex Numbers section of Coddy's Algebra 2 journey. Lesson 31 of 48.

The discriminant sits under the square root in the formula, and a square root behaves in three ways depending on the sign of what is under it. So, when a, b and c are real, the sign tells you what the answers look like before you solve anything.

Positive: the root is a real number and the ± gives two different real answers. x2−6x+5=0{x}^{2}-6x+5 = 0 has discriminant 16, and its solutions are 1 and 5. Zero: the root is 0, so adding it and subtracting it give the same number. x2+2x+1=0{x}^{2}+2x+1 = 0 has discriminant 4−44-4, and its only solution, -1, is called a repeated solution.

Negative: the root of a negative number needs i, so both answers are complex. For x2+2x+5=0{x}^{2}+2x+5 = 0 the discriminant is 4−204-20, which is -16, and the formula gives −2±−162\frac{-2\pm\sqrt{-16}}{2}: x=−1+2ix = -1+2i and x=−1−2ix = -1-2i. The ± makes them conjugates, with the same real part and opposite imaginary parts. When a, b and c are real, complex solutions always come in such a pair.

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

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