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Drawing from Standard Form

Part of the Quadratics & Complex Numbers section of Coddy's Algebra 2 journey. Lesson 4 of 51.

To draw a parabola given in standard form, find the vertex first, then use a to place a second point. Take y = x^2 + 2x - 3. The axis is x = -2/(2 × 1), which is -1, and the height there is 1 - 2 - 3, which is -4. The vertex is (-1, -4).

Now the second point. As with vertex form, one step to the side of the vertex the curve moves by a. Here a is 1, so one step right, at x = 0, the height is -4 + 1 = -3. That gives (0, -3).

There is a free check: at x = 0 every term with x vanishes, so the curve meets the y-axis at c. Here c is -3, which matches the point just found. If a were 2, one step from the vertex the curve would rise 2 instead.

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Challenge

Draw the graph of y = x^2 - 4x + 3. Find the vertex with -b/(2a) and the rule, then drag the vertex and the second point.

Try it yourself

y = x^2 - 4x + 3

Draw the graph

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