Dilution
Part of the Stoichiometry section of Coddy's Chemistry journey. Lesson 16 of 41.
Adding water dilutes a solution. The moles of solute stay the same and spread through a bigger volume, so the concentration falls:
c₁V₁ = c₂V₂
of CaCl₂ plus of water makes : .
Same particles, five times the volume
V₂ is the total volume, not the water added. The ions follow: [Ca²⁺] = , [Cl⁻] = .
Challenge
of MgCl₂ is poured into a flask, and of water is added. MgCl₂ dissolves as MgCl₂(s) → Mg²⁺(aq) + 2Cl⁻(aq). What is [Cl⁻] in the diluted solution?
Try it yourself
Solve for
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Stoichiometry
3Solutions
Molar ConcentrationPreparing a SolutionIons in SolutionIon ConcentrationsDilutionRecap - Lab Prep6Practice Problems
Recap - Fertilizer PlantRecap - Acid for the PlantRecap - Gases for AmmoniaRecap - Ions in the SampleRecap - The Full PlantRecap - Bromide in BrineRecap - Chlorine for BromineRecap - Magnesium BromideRecap - Silver Bromide TestRecap - Balloon at LaunchRecap - Balloon High UpRecap - Before It BurstsRecap - Hydrogen from Water