Reactions in Solution

Part of the Stoichiometry section of Coddy's Chemistry journey. Lesson 22 of 41.

A dissolved reactant's moles are $n = c \times V$ , V in liters. Then the mole ratio as usual.

Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g). $50\ \mathrm{mL}$ of $2\ \mathrm{M}$ HCl is $0.1\ \mathrm{mol}$ , which uses $0.05\ \mathrm{mol}$ of Mg: $1.2\ \mathrm{g}$ .

A balance with 1.2 g of magnesium beside 50 mL of 2 M hydrochloric acid

1.2 g of Mg for 50 mL of 2 M HCl

Backwards, the volume of solution that holds n moles is $V = \frac{n}{c}$ .

Challenge

Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g). What volume of $0.5\ \mathrm{M}$ HCl, in mL, reacts completely with $2.4\ \mathrm{g}$ of magnesium?

Try it yourself

Solve for $V$

Test yourself

This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Stoichiometry

1The Mole

Counting Particles: the Mole Avogadro's Number Molar Mass Mass, Moles and Particles Moles in a Formula Recap - Mole Bridge

4Equations and Mole Ratios

Balancing Equations Reading an Equation in Moles Mass to Mass Gas Volumes in ReactionsReactions in SolutionPrecipitation Recap - Rocket Fuel

2Gases

Molar Volume of a Gas Avogadro's Law Pressure, Volume, Temperature The Ideal Gas Law Recap - Weather Balloon

5Limiting Reactant

The Limiting Reactant What Is Left Over Industrial Scale Recap - Aluminum Plant

3Solutions

Molar Concentration Preparing a Solution Ions in Solution Ion Concentrations Dilution Recap - Lab Prep

6Practice Problems

Recap - Fertilizer Plant Recap - Acid for the Plant Recap - Gases for Ammonia Recap - Ions in the Sample Recap - The Full Plant Recap - Bromide in Brine Recap - Chlorine for Bromine Recap - Magnesium Bromide Recap - Silver Bromide Test Recap - Balloon at Launch Recap - Balloon High Up Recap - Before It Bursts Recap - Hydrogen from Water