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The Ideal Gas Law

Part of the Stoichiometry section of Coddy's Chemistry journey. Lesson 10 of 41.

The ideal gas law ties pressure, volume, moles and temperature together:

P⋅V=n⋅R⋅TP \cdot V = n \cdot R \cdot T

P in atm, V in L, n in mol, T in kelvin, R=0.082 atm L/(mol K)R = 0.082\ \mathrm{atm\,L/(mol\,K)}.

Know three and the law gives the fourth: one mole at 2 atm2\ \mathrm{atm} and 300 K300\ \mathrm{K} takes 12.3 L12.3\ \mathrm{L}.

One mole of gas at 2 atm, 12.3 L and 300 K

P·V = n·R·T

At 1 atm and 298 K one mole takes about 24.4 L24.4\ \mathrm{L}: the 25 L rule. With the moles, m=n×Mm = n \times M gives the mass.

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Challenge

A steel tank holds 2 mol2\ \mathrm{mol} of nitrogen, N₂, at 3 atm3\ \mathrm{atm} and 450 K450\ \mathrm{K}. What is the volume VV of the tank?

Try it yourself

Physics diagram: gasbox

Solve for VV

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

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