Precipitation

Part of the Stoichiometry section of Coddy's Chemistry journey. Lesson 23 of 41.

Mix AgNO₃(aq) with NaBr(aq) and a pale yellow solid, AgBr, appears: a precipitate, a solid formed from two solutions.

AgNO₃(aq) + NaBr(aq) → AgBr(s) + NaNO₃(aq)

Na⁺ and NO₃⁻ stay dissolved: spectator ions. Without them, the net ionic equation:

Ag⁺(aq) + Br⁻(aq) → AgBr(s)

$50\ \mathrm{mL}$ of $0.2\ \mathrm{M}$ AgNO₃ gives $0.01\ \mathrm{mol}$ of AgBr: $1.88\ \mathrm{g}$ .

Silver bromide forming in a beaker, and 1.88 g of it on a balance

Filtered, dried, weighed

Challenge

Silver nitrate solution is added to $30\ \mathrm{mL}$ of $0.5\ \mathrm{M}$ NaBr until all the Br⁻ has reacted: Ag⁺(aq) + Br⁻(aq) → AgBr(s). What mass of AgBr ( $188\ \mathrm{g/mol}$ ) forms?

Try it yourself

Solve for $m$

Test yourself

This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Stoichiometry

1The Mole

Counting Particles: the Mole Avogadro's Number Molar Mass Mass, Moles and Particles Moles in a Formula Recap - Mole Bridge

4Equations and Mole Ratios

Balancing Equations Reading an Equation in Moles Mass to Mass Gas Volumes in Reactions Reactions in SolutionPrecipitationRecap - Rocket Fuel

2Gases

Molar Volume of a Gas Avogadro's Law Pressure, Volume, Temperature The Ideal Gas Law Recap - Weather Balloon

5Limiting Reactant

The Limiting Reactant What Is Left Over Industrial Scale Recap - Aluminum Plant

3Solutions

Molar Concentration Preparing a Solution Ions in Solution Ion Concentrations Dilution Recap - Lab Prep

6Practice Problems

Recap - Fertilizer Plant Recap - Acid for the Plant Recap - Gases for Ammonia Recap - Ions in the Sample Recap - The Full Plant Recap - Bromide in Brine Recap - Chlorine for Bromine Recap - Magnesium Bromide Recap - Silver Bromide Test Recap - Balloon at Launch Recap - Balloon High Up Recap - Before It Bursts Recap - Hydrogen from Water