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Mass, Moles and Particles

Part of the Stoichiometry section of Coddy's Chemistry journey. Lesson 4 of 41.

The mole is the bridge between a mass you can weigh and a number of particles you cannot count:

n=mMN=n×NAn = \frac{m}{M} \qquad N = n \times N_A

9 g9\ \mathrm{g} of water (18 g/mol18\ \mathrm{g/mol}) is 9 / 18 = 0.5 mol0.5\ \mathrm{mol}, and 0.5 × 6.02×10236.02 \times 10^{23} = 3.01×10233.01 \times 10^{23} molecules.

A balance reading 9 g of water

9 g of water: half a mole

Particles back to mass: divide by N_A, then multiply by MM.

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Challenge

A silver ring weighs 5.4 g5.4\ \mathrm{g}. How many silver atoms NN does it hold?

Try it yourself

Physics diagram: balance

Solve for NN

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Stoichiometry