Molar Concentration

Part of the Stoichiometry section of Coddy's Chemistry journey. Lesson 12 of 41.

A solution is a solute dissolved in a solvent, here always water. Salt water is a solution of NaCl.

The molar concentration is the moles of solute in each liter of solution:

$c = \frac{n}{V}$

Its unit is mol/L, written M: $0.5\ \mathrm{mol}$ in $1\ \mathrm{L}$ is $0.5\ \mathrm{M}$ .

V is in liters: $250\ \mathrm{mL}$ is $0.250\ \mathrm{L}$ . Turned around, $n = c \times V$ gives the moles in a volume.

A beaker holding 250 mL of 0.5 M sodium chloride solution

250 mL of 0.5 M NaCl holds 0.125 mol

Challenge

A sports drink holds $0.06\ \mathrm{mol}$ of glucose in a $500\ \mathrm{mL}$ bottle. What is the concentration of glucose, in M?

Try it yourself

Solve for $c$

Test yourself

This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Stoichiometry

1The Mole

4Equations and Mole Ratios

2Gases

5Limiting Reactant

3Solutions

6Practice Problems