Menu

Gather Toward the Larger

Part of the Inequalities & Absolute Value section of Coddy's Algebra journey. Lesson 20 of 61.

In 5−x<2x−45-x < 2x-4, the x-terms are −x-x on the left and 2x2x on the right. Collect them on the side with the larger coefficient. Here that is the right side, because 2 is larger than -1. Then the coefficient stays positive and you never need to flip the sign. Add xx to both sides:

5<3x−45 < 3x-4

9<3x9 < 3x

3<x3 < x

The last line says that 3 is less than xx. Written with xx first, it is x>3x > 3.

You could collect the x-terms on the left instead. Subtracting 2x2x from both sides and then subtracting 5 gives −3x<−9-3x < -9. Dividing by -3 and flipping the sign gives x>3x > 3 again. Both ways give the same answer. Collecting toward the larger coefficient avoids the division by a negative number.

challenge icon

Challenge

Medium

Solve 7−2x≤x−57-2x \le x-5.

Try it yourself

7−2x≤x−57-2x \le x-5

Get xx alone on one side

All lessons in Inequalities & Absolute Value