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With a Fraction

Part of the Inequalities & Absolute Value section of Coddy's Algebra journey. Lesson 16 of 61.

To solve x2−1>3\frac{x}{2}-1 > 3, add 1 to both sides, then multiply both sides by 2. Neither step changes the sign, because 2 is positive:

x2>4\frac{x}{2} > 4

x>8x > 8

You can also clear the fraction first. Multiply every term by 2 to get x−2>6x-2 > 6, then add 2 to both sides. This gives the same answer in the same number of steps.

When a whole side is one fraction, clearing the denominator is a good first step. For x+13≤2\frac{x+1}{3} \le 2, multiply both sides by 3 to get x+1≤6x+1 \le 6. Then subtract 1 from both sides to get x≤5x \le 5.

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Challenge

Easy

Solve the inequality x3+2≤4\frac{x}{3}+2 \le 4 for xx.

Try it yourself

x3+2≤4\frac{x}{3}+2 \le 4

Get xx alone on one side

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