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The Flip

Part of the Inequalities & Absolute Value section of Coddy's Algebra journey. Lesson 10 of 61.

Multiplying by a negative number works differently. Start from a true statement: 2<52 < 5. Multiply both sides by -1. The left side becomes −2-2 and the right side becomes −5-5. Now compare them. On the number line, -2 is to the right of -5, so −2>−5-2 > -5. The order reversed.

2 is left of 5, but -2 is right of -5: multiplying by a negative turns the order around

2 is to the left of 5, but -2 is to the right of -5. Multiplying by a negative number reverses the order.

When you multiply or divide both sides of an inequality by a negative number, the sign flips. A < becomes a >, a ≤ becomes a ≥, and the other way round. To solve −2x<6-2x < 6, divide both sides by -2 and flip the sign:

x>−3x > -3

Check the answer with x=0x = 0. It satisfies x>−3x > -3, and in the original inequality −2⋅0=0-2\cdot 0 = 0, which is less than 6. If you did not flip the sign, you would get x<−3x < -3, which includes -10. But −2⋅(−10)=20-2\cdot \left(-10\right) = 20, and 20 is not less than 6, so that answer is wrong.

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Challenge

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Solve −5x≤30-5x \le 30.

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−5x≤30-5x \le 30

Get xx alone on one side

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