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Subtract, Then Flip

Part of the Inequalities & Absolute Value section of Coddy's Algebra journey. Lesson 15 of 61.

To solve 5−2x≥15-2x \ge 1, subtract 5 from both sides. The sign stays the same, and you get −2x≥−4-2x \ge -4. Now the coefficient of xx is -2. Divide both sides by -2 and flip the sign:

x≤2x \le 2

There are two steps, and one of them divides by a negative number, so the sign flips once. Check the answer with x=0x = 0. It is at most 2, and 5−2⋅0=55-2\cdot 0 = 5, which is at least 1.

The sign flips at the step where you divide by the negative coefficient, not before. Subtracting 5 is an ordinary subtraction, and it leaves the sign alone. Ask two separate questions at each step: what are you undoing, and are you multiplying or dividing by a negative number?

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Challenge

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Solve 10−3x>110-3x > 1.

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10−3x>110-3x > 1

Get xx alone on one side

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