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Outside, Shifted

Part of the Inequalities & Absolute Value section of Coddy's Algebra journey. Lesson 48 of 61.

In ∣2x+1∣≥5\left|2x+1\right| \ge 5, the expression inside the bars is 2x+12x+1. Split into the two cases, then solve each case as a two-step inequality.

2x+1≥52x+1 \ge 5

2x≥42x \ge 4

x≥2x \ge 2

or

2x+1≤−52x+1 \le -5

2x≤−62x \le -6

x≤−3x \le -3

The solution is x≤−3x \le -3 or x≥2x \ge 2. On a number line, these are two rays pointing away from each other.

Solve each case with the ordinary inequality rules. If a case has a negative coefficient, flip the sign when you divide, as usual. Keep both cases to the end, and keep the word "or" between the two answers.

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Challenge

Medium

Solve the inequality ∣x−3∣>1\left|x-3\right| > 1 for xx.

Try it yourself

∣x−3∣>1\left|x-3\right| > 1

Get xx alone on one side

All lessons in Inequalities & Absolute Value