Isolate the Bars First
Part of the Inequalities & Absolute Value section of Coddy's Algebra journey. Lesson 44 of 64.
In |x + 3| - 2 = 4, the absolute value is not alone on its side. Before you split, get the absolute value by itself. Add 2 to both sides:
|x + 3| = 6
Now split into two cases: x + 3 = 6 or x + 3 = -6. Subtract 3 in each case to get x = 3 or x = -9.
The -2 in |x + 3| - 2 = 4 sits outside the absolute value bars, so it is not part of either case. Add 2 to both sides first to get |x + 3| = 6. Then solve x + 3 = 6 and x + 3 = -6 separately.
Challenge
MediumSolve |x - 5| + 2 = 8.
Try it yourself
Solve for x
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Inequalities & Absolute Value
1What an Inequality Is
The Four SignsA Picture on a LineClosed or OpenReading It BackwardsRecap: What an Inequality Is4Two-Step Inequalities
Two StepsSubtract, Then FlipWith a FractionA Bracket on the WayRecap: Two-Step Inequalities2Adding and Subtracting
Add to Both SidesSubtract from Both SidesNegatives in the MixSolve, Then DrawRecap: Adding and Subtracting5Variables on Both Sides
x on Both SidesGather Toward the LargerBrackets FirstAlways True, Never TrueRecap: Variables on Both Sides11From Words to Inequalities
At Least, At MostMore ThanA Budget That ShrinksTwo LimitsRecap: From Words3Multiplying and Dividing
Divide by a PositiveMultiply by a PositiveThe FlipDividing by a NegativeNegative FractionsRecap: Multiply and Divide6Graphing Solutions
From Inequality to PictureIs the Endpoint In?A Flip on the LineRecap: Graphing Solutions9Absolute Value Equations
Distance from ZeroThe Equation |x| = 3Distance from a PointIsolate the Bars FirstA Coefficient InsideNo Solution, One SolutionRecap: Absolute Equations