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Isolate the Bars First

Part of the Inequalities & Absolute Value section of Coddy's Algebra journey. Lesson 44 of 64.

In |x + 3| - 2 = 4, the absolute value is not alone on its side. Before you split, get the absolute value by itself. Add 2 to both sides:

|x + 3| = 6

Now split into two cases: x + 3 = 6 or x + 3 = -6. Subtract 3 in each case to get x = 3 or x = -9.

The -2 in |x + 3| - 2 = 4 sits outside the absolute value bars, so it is not part of either case. Add 2 to both sides first to get |x + 3| = 6. Then solve x + 3 = 6 and x + 3 = -6 separately.

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Challenge

Medium

Solve |x - 5| + 2 = 8.

Try it yourself

|x - 5| + 2 = 8

Solve for x

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