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Solving a Chain

Part of the Inequalities & Absolute Value section of Coddy's Algebra journey. Lesson 29 of 61.

To solve a chain, get xx alone in the middle. In −3<x+1<5-3 < x+1 < 5, the middle is x+1x+1. Whatever you do to the middle, you must do to all three parts, because the middle is compared with both ends. Subtract 1 from all three parts:

−3−1<x+1−1<5−1-3-1 < x+1-1 < 5-1

−4<x<4-4 < x < 4

One step solves the chain. xx is between -4 and 4.

A chain is two inequalities, −3<x+1-3 < x+1 and x+1<5x+1 < 5. Subtracting 1 from all three parts is the same as subtracting 1 from both sides of each inequality. Writing them as one chain lets you do both steps in one line. When xx is alone in the middle, the two ends give the answer.

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Challenge

Medium

Solve the compound inequality 2<x+4<92 < x+4 < 9 for xx.

Try it yourself

2<x+4<92 < x+4 < 9

Get xx alone in the middle

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