Is JavaScript good for data structures and algorithms?
Yes, especially if you are heading for frontend or full-stack roles, where it is the language you will interview in. Three quirks are worth learning early: there is no built-in heap or queue, sort() compares as strings unless you pass a comparator, and every number is a 64-bit float, so integers beyond 2^53 need BigInt.
Does JavaScript have a built-in heap or priority queue?
No. You get Array, Map, Set and their weak variants, and that is all. In an interview you either write a small binary heap, about thirty lines, or say you would use one and state its costs; either way you need to have written one before. Step two of this path is where you do.
Why does [10, 9, 1].sort() return [1, 10, 9]?
Because without a comparator Array.prototype.sort converts the elements to strings and compares them in UTF-16 order, and '10' comes before '9'. Sort numbers with nums.sort((a, b) => a - b). It is the first bug most people meet when they start writing sorting code in JavaScript.
Do frontend interviews ask data structures and algorithms?
At many larger companies, yes: usually one or two rounds of arrays, hash maps, trees and graph traversal, in JavaScript, beside the UI and system design rounds. Smaller companies lean more on practical tasks. Either way, knowing that a Map lookup is constant time and a nested loop over two lists is not is what separates a working answer from a fast one.
Which courses on this path are not taught in JavaScript?
Three: dynamic programming and the Python interview series are taught in Python, and bit manipulation in C++. They are listed after the steps, each with a link that opens it in its own language. JavaScript has the same bitwise operators, plus >>>, but applies them to 32-bit integers, which is worth remembering when you port a trick.
Do I need to know JavaScript before starting this path?
Functions, arrays, objects and classes, at least. If those are new, Coddy's JavaScript course covers them first, free, and this path picks up where it ends.