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A Negative Inside

Part of the Trig Equations and Inverses section of Coddy's Trigonometry journey. Lesson 17 of 56.

A negative input moves the inner angle out of quadrant I, and the range decides where. θ = arcsin(−3/5) is between −90° and 0°, in quadrant IV, where the point is (4, −3) on a circle of radius 5. So tan(arcsin(−3/5)) = −3/4, but cos(arcsin(−3/5)) = 4/5 is positive: cosine is positive in quadrant IV.

Arccos of a negative number is in quadrant II, between 90° and 180°, where x is negative and y positive. Work the sizes out on a triangle as before, then give each side the sign of its quadrant.

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Challenge

Find the exact value of y = sin(arccos(−4/5)). Write y = … as a fraction and press Check.

Try it yourself

y = sin(acos(-4/5))

Solve for y

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