Menu

An Angle From a Slope

Part of the Trig Equations and Inverses section of Coddy's Trigonometry journey. Lesson 9 of 52.

A road sign says 12%, and most people read it as a 12° slope. It is not.

A right triangle with a rise of 12 over a run of 100 and the angle θ at its foot

12% means the road rises 12 m for every 100 m along. So tan⁡(θ)=12100\tan\left(\theta\right) = \frac{12}{100}, and θ is arctan⁡(0.12)\arctan\left(0.12\right), about 6.84°. A road going down has a negative grade and a negative angle: arctan(−c) = −arctan(c).

challenge icon

Challenge

A road drops 8 m for every 100 m along. That is a grade of −8%, so tan⁡(x)=−0.08\tan\left(x\right) = -0.08. Find its angle x to two decimal places. The angle is negative because the road goes down. Done means x is in degrees with 2 decimals.

Then press Check.

Try it yourself

tan⁡x=−0.08\tan x = -0.08

Get xx alone−90∘<x<90∘-90^{\circ} < x < 90^{\circ}

All lessons in Trig Equations and Inverses