Menu

Why arcsin Gives One Angle

Part of the Trig Equations and Inverses section of Coddy's Trigonometry journey. Lesson 4 of 52.

The sine wave from minus 180 to 450 degrees; the line at height one half meets it again and again

The line at height 1/2 meets the sine wave again and again: sin⁡(30∘)\sin\left(30^{\circ}\right), sin⁡(150∘)\sin\left(150^{\circ}\right) and sin⁡(390∘)\sin\left(390^{\circ}\right) are all 1/2. arcsin(c) means the angle whose sine is c. It must give one answer, so it uses one part of the wave.

From −90° to 90°, the sine goes from −1 up to 1 and meets each value once. These angles are arcsin's range: the only angles it gives back. So a negative input gives a negative angle: arcsin⁡(−12)=−30∘\arcsin\left(\frac{-1}{2}\right) = -30^{\circ}, never 330°.

challenge icon

Challenge

Work out x=arcsin⁡(−32)x = \arcsin\left(\frac{-\sqrt{3}}{2}\right) in degrees. Write it as the next line, x = …°.

Then press Check.

Try it yourself

x=arcsin⁡(−32)x = \arcsin\left(\frac{-\sqrt{3}}{2}\right)

Get xx alone−90∘≤x≤90∘-90^{\circ} \le x \le 90^{\circ}

All lessons in Trig Equations and Inverses