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Half Angles

Part of the Trig Equations and Inverses section of Coddy's Trigonometry journey. Lesson 34 of 52.

A half angle runs the other way. In 2sin⁡(x2)=12\sin\left(\frac{x}{2}\right) = 1, while x runs over [0°, 360°), x/2 runs over [0°, 180°): only half a turn. sin(x/2) = 1/2 at x/2 = 30° or 150°, both in that half turn, so x = 60° or 300°.

A half turn can also hold fewer answers than a full one. cos(x/2) = −1/2 needs x/2 = 120° or 240°, and only 120° is below 180°: one answer, x = 240°.

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Challenge

Solve 2cos⁡(x2)=22\cos\left(\frac{x}{2}\right) = \sqrt{2} for every x in [0°, 360°), then press Check.

Try it yourself

2cos⁡(x2)=22\cos\left(\frac{x}{2}\right) = \sqrt{2}

Get xx alone0∘≤x<360∘0^{\circ} \le x < 360^{\circ}

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