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Solving sin 2x

Part of the Trig Equations and Inverses section of Coddy's Trigonometry journey. Lesson 33 of 52.

Solve 2sin⁡(2x)=12\sin\left(2x\right) = 1 on [0°, 360°). Divide by 2: sin⁡(2x)=12\sin\left(2x\right) = \frac{1}{2}. Over two turns, 2x = 30°, 150°, 390° or 510°. Halve each: x = 15°, 75°, 195° or 255°.

Check one: x = 195° gives 2x = 390°, which ends where 30° does, and sin 30° is 1/2. On the board the arcsin chip knows 2x makes two turns and writes all four cases; the halving is yours to check.

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Challenge

Solve 2sin⁡(2x)=32\sin\left(2x\right) = \sqrt{3} for every x in [0°, 360°), then press Check.

Try it yourself

2sin⁡2x=32\sin 2x = \sqrt{3}

Get xx alone0∘≤x<360∘0^{\circ} \le x < 360^{\circ}

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