One Equation, Two Angles
Part of the Trig Equations and Inverses section of Coddy's Trigonometry journey. Lesson 1 of 56.
Solve 2sin(x) = √2 for every x in [0°, 360°). Get the sine alone first: divide both sides by 2 and you have sin(x) = √2/2. The special value sin(45°) = √2/2 gives one answer, 45°.
Sine is the height of a point on the unit circle, and that height is reached twice in one turn: at 45° and at its mirror image across the y axis, 180° − 45°, which is 135°. Cosine is the x coordinate, so its mirror is across the x axis: the partner of an angle a is 360° − a.
One turn of the sine wave crosses the height √2/2 twice.
Challenge
Solve 2cos(x) = 1 for every x in [0°, 360°). Get the cosine alone, then use the chip that finds every angle, and press Check.
Try it yourself
Solve for x
This lesson includes a short quiz. Start the lesson to answer it and track your progress.
All lessons in Trig Equations and Inverses
1Your First Trig Equations
One Equation, Two AnglesReading Signs on the CircleThe Reference AngleRecap: First Equations4Compositions
Draw the TriangleThe Outer FunctionA Negative InsideWhen Undoing Does Not UndoRecap: Compositions2Inverses and Their Ranges
Why arcsin Gives One AngleNegative Inputs to arcsinThe Range of arccosThe Range of arctanRecap: Inverse Ranges5Equations on a Domain
A Negative CosineTangent EquationsEquations in RadiansTwo Turns, Four AnswersRecap: On a Domain