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One Equation, Two Angles

Part of the Trig Equations and Inverses section of Coddy's Trigonometry journey. Lesson 1 of 56.

Solve 2sin(x) = √2 for every x in [0°, 360°). Get the sine alone first: divide both sides by 2 and you have sin(x) = √2/2. The special value sin(45°) = √2/2 gives one answer, 45°.

Sine is the height of a point on the unit circle, and that height is reached twice in one turn: at 45° and at its mirror image across the y axis, 180° − 45°, which is 135°. Cosine is the x coordinate, so its mirror is across the x axis: the partner of an angle a is 360° − a.

The sine wave over one turn and the dashed line at height root 2 over 2

One turn of the sine wave crosses the height √2/2 twice.

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Challenge

Solve 2cos(x) = 1 for every x in [0°, 360°). Get the cosine alone, then use the chip that finds every angle, and press Check.

Try it yourself

2cos(x) = 1

Solve for x

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Trig Equations and Inverses