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Every Solution of sin 3x

Part of the Trig Equations and Inverses section of Coddy's Trigonometry journey. Lesson 35 of 52.

For every solution of sin⁡(2x)=12\sin\left(2x\right) = \frac{1}{2}, write the families for 2x first: 2x=30∘+360∘⋅k2x = 30^{\circ}+360^{\circ}\cdot k or 2x=150∘+360∘⋅k2x = 150^{\circ}+360^{\circ}\cdot k. Then divide everything by 2, the period too:

x=15∘+180∘⋅kx = 15^{\circ}+180^{\circ}\cdot k

x=75∘+180∘⋅kx = 75^{\circ}+180^{\circ}\cdot k

The most common slip is halving the 30° and keeping 360°k. That family misses 195° and every other answer. A multiple angle shrinks the period: sin 2x repeats every 180°, sin 3x every 120°.

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Challenge

Find every solution of 2sin⁡(3x)=12\sin\left(3x\right) = 1, with k any integer, and press Check.

Try it yourself

2sin⁡3x=12\sin 3x = 1

Get xx aloneAll solutions, k any integer

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