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Changing a Capacitor

Part of the Electricity and Magnetism section of Coddy's Physics journey. Lesson 19 of 51.

A dielectric between the plates multiplies the capacitance by κ:

C = κ ε₀ A / d

A capacitor with a dielectric

Still connected to the battery: V stays the same. Disconnected: Q stays the same. Then use Q = C V with the new C.

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Challenge

A 2 μF capacitor is charged to 50 V and disconnected. Its plates are then pulled apart to twice the distance. What is its voltage V_2 now?

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