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Discharging a Capacitor

Part of the Electricity and Magnetism section of Coddy's Physics journey. Lesson 36 of 51.

Discharging through a resistor:

q=Q e−t/RCq = Q\,e^{-t/RC}

A discharging circuit

After one τ=RC\tau = RC, 37% is left. The voltage falls the same way, and the stored energy becomes heat in the resistor.

The discharging curve

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Challenge

A 200 μF200\ \mathrm{\mu F} capacitor charged to 10 V10\ \mathrm{V} discharges through a 5 kΩ5\ \mathrm{k\Omega } resistor. How much charge qq is left 2 s2\ \mathrm{s} later?

Try it yourself

Physics diagram: circuit

Solve for qq

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