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Internal Resistance

Part of the Electricity and Magnetism section of Coddy's Physics journey. Lesson 26 of 51.

A real battery has an EMF ε and an internal resistance r:

ε=I(R+r)\varepsilon = I(R + r)

A battery with internal resistance

The voltage at its ends drops as the current grows:

V=ε−IrV = \varepsilon - Ir

Its efficiency is Vε=RR+r\frac{V}{\varepsilon} = \frac{R}{R + r}.

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Challenge

A battery with EMF 12 V12\ \mathrm{V} and internal resistance 0.5 Ω0.5\ \mathrm{\Omega } is connected to a 5.5 Ω5.5\ \mathrm{\Omega } resistor. What is the voltage VV at the battery's ends?

Try it yourself

Physics diagram: circuit

Solve for VV

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