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Resistance and Ohm's Law

Part of the Electricity and Magnetism section of Coddy's Physics journey. Lesson 22 of 51.

Ohm's law: the current through a resistor is proportional to the voltage across it:

V=IRV = IR

with R in ohms (1 Ω1\ \mathrm{\Omega } = 1 V/A1\ \mathrm{V/A}).

A battery and a resistor

A wire's resistance:

R=ρ LAR = \rho\,\frac{L}{A}

Longer: more resistance; thicker: less. ρ, the resistivity, belongs to the material.

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Challenge

A copper wire is 10 m10\ \mathrm{m} long with a cross-section of 1 mm21\ \mathrm{mm^2} (1×10−6 m21\times10^{-6}\ \mathrm{m²}). Copper's resistivity is 1.7×10−8 Ω⋅m1.7\times10^{-8}\ \mathrm{Ω·m}. What current II flows when 1.7 V1.7\ \mathrm{V} is put across the wire? Work out its resistance first.

Try it yourself

Physics diagram: circuit

Solve for II

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