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Field and Potential

Part of the Electricity and Magnetism section of Coddy's Physics journey. Lesson 12 of 51.

In a uniform field, between plates a distance d apart with a voltage V across them:

E=VdE = \frac{V}{d}

1 V/m1\ \mathrm{V/m} = 1 N/C1\ \mathrm{N/C}.

Equipotentials across a uniform field

The field points from high to low potential. Equipotentials cross the field at right angles; moving a charge along one takes no work.

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Challenge

Two horizontal plates 0.05 m0.05\ \mathrm{m} apart are connected to 200 V200\ \mathrm{V}, the top plate at 200 V200\ \mathrm{V} and the bottom one at 0 V0\ \mathrm{V}. An electron sits between them, and its weight is far too small to count. Draw the force on the electron, then find how big it is, FF.

Try it yourself

Physics diagram: plates, charge

Solve for FF

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