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Horizontal Circles

Part of the Mechanics section of Coddy's Physics journey. Lesson 77 of 97.

A net force toward the centre keeps an object on its circle:

Fnet=mv2rF_{\text{net}} = \frac{m v^2}{r}

It is not a new force: a tension, a friction or a normal force does the job.

A puck on a string: T=mv2/r\relax T = mv^2/r.

Seen from above: a puck on a frictionless table, tied by a string to a peg at the centre of its circular path; the tension T pulls the puck along the string toward the peg while its velocity v points along the circle

Seen from above: the string tension is the force toward the centre.

A car on a flat curve: fs=mv2/r\relax f_s = mv^2/r, up to the friction limit.

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Challenge

A 0.2 kg0.2\ \mathrm{kg} puck slides in a circle on frictionless ice, tied to a 0.5 m0.5\ \mathrm{m} string from a peg at the centre. The string breaks at a tension of 10 N10\ \mathrm{N}. Find the fastest speed vv the puck can go.

Try it yourself

Physics diagram: pulley, rope, ball

Solve for vv

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

All lessons in Mechanics