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Work

Part of the Mechanics section of Coddy's Physics journey. Lesson 50 of 97.

A force does work on an object when the object moves while the force acts. Only the part of the force along the motion counts:

W=Fdcos⁡θW = F d \cos\theta

θ\theta is the angle between the force and the displacement. Work is in joules.

A sled on flat snow pulled by a rope force F at angle theta above the ground; the dashed part F cos theta lies along the displacement d, which points to the right

Only the part of F along the displacement d does work.

A force perpendicular to the motion does no work: cos⁡90∘=0\cos 90^\circ = 0.

A force against the motion, like friction, does negative work: cos⁡180∘=−1\cos 180^\circ = -1.

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Challenge

A child pulls a 10 kg10\ \mathrm{kg} wagon along smooth, level ground by its handle with 30 N30\ \mathrm{N} at 60∘60^\circ above the ground, and the pull does 300 J300\ \mathrm{J} of work. Draw the forces on the wagon, then find how far it moves. Call the distance dd.

Try it yourself

Physics diagram: cart, rope, vec; arrows d = ?

Solve for dd

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