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Impulse

Part of the Mechanics section of Coddy's Physics journey. Lesson 66 of 97.

The impulse J\relax J is the net force times the time it acts. It equals the change in momentum:

J=FΔt=ΔpJ = F\Delta t = \Delta p

Its unit is N·s, the same as kg·m/s.

The same change in momentum can come from a large force over a short time or a small force over a long time: a crash mat makes the stop last longer, so the force is smaller.

Two force against time graphs: a tall rectangle of 800 newtons lasting 0.1 seconds and a low, wide rectangle of 200 newtons lasting 0.4 seconds; both shaded areas are 80 newton seconds

The area under each graph is the impulse: 800 · 0.1 = 200 · 0.4 = 80 N⋅s80\ \mathrm{N\cdot s}.

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Challenge

A 60 kg60\ \mathrm{kg} stunt performer falls onto an air cushion at 8 m/s8\ \mathrm{m/s} and is stopped in 0.4 s0.4\ \mathrm{s}. Taking up as positive, find the net force F\relax F on her while she stops.

Try it yourself

Physics diagram: crate; arrows F = ?, v i = −8 m/s

Solve for FF

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

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