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Inelastic Collisions

Part of the Mechanics section of Coddy's Physics journey. Lesson 69 of 97.

In an inelastic collision some kinetic energy is lost, but momentum is conserved. Bodies that stick together share one velocity:

m1v1+m2v2=(m1+m2) v′m_1 v_1 + m_2 v_2 = (m_1 + m_2)\, v'

In the picture: 2 · 6 = 3v', so v' = 4 m/s4\ \mathrm{m/s}. The kinetic energy drops from 36 J36\ \mathrm{J} to 24 J24\ \mathrm{J}.

Before: a 2 kilogram cart at 6 metres per second moves right toward a 1 kilogram cart at rest. After: the two carts are locked together and move right as one at 4 metres per second

Perfectly inelastic: the carts stick and share one velocity.

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Challenge

A 3 kg3\ \mathrm{kg} cart rolls right at 4 m/s4\ \mathrm{m/s}, and a 1 kg1\ \mathrm{kg} cart rolls left at 2 m/s2\ \mathrm{m/s} toward it. They meet and stick together. Taking right as positive, find their velocity vf\relax v_{f} after the collision.

Try it yourself

Physics diagram: cart; arrows v 1 = 4 m/s, v 2 = −2 m/s, v f = ?

Solve for vfv_{f}

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