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Momentum as a Vector

Part of the Mechanics section of Coddy's Physics journey. Lesson 71 of 97.

In two dimensions momentum is a vector along the velocity. It splits into components:

px=mvcos⁡θ,py=mvsin⁡θp_x = mv\cos\theta, \quad p_y = mv\sin\theta

A ball's momentum vector p at angle theta above the x axis, split into a horizontal component px along the axis and a vertical component py

The components of p are the sides of a right triangle, like any vector.

Back to the size: p=px2+py2p = \sqrt{p_x^2 + p_y^2}. A component pointing the negative way is negative.

In a collision the total px\relax p_x and the total py\relax p_y each stay the same.

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Challenge

A 0.8 kg0.8\ \mathrm{kg} ball is thrown at 60∘60^\circ above the ground, and its horizontal momentum is 12 kg⋅m/s12\ \mathrm{kg\cdot m/s}. Find its speed vv.

Try it yourself

Physics diagram: ball, vec; arrows v = ?, p x = 12 kg·m/s

Solve for vv

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

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