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A Point and a Slope

Part of the Graphs & Systems section of Coddy's Algebra journey. Lesson 23 of 64.

A line is fixed by one point on it and its slope. Point-slope form writes the equation of the line through the point (x1, y1) with slope m:

y - y1 = m(x - x1)

For the line through (1, 2) with slope 3, substitute the point and the slope: y - 2 = 3(x - 1). To change it into slope-intercept form, expand the bracket to get y - 2 = 3x - 3. Then add 2 to both sides to get y = 3x - 1.

Point-slope form comes from the slope formula. Take any point (x, y) on the line. The rise from (x1, y1) to (x, y) is y - y1 and the run is x - x1, so (y - y1)/(x - x1) = m. Multiply both sides by the run x - x1 to get y - y1 = m(x - x1). To use the form, substitute the known point and the slope, then expand the bracket.

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Challenge

Medium

Rewrite y - 4 = 2(x - 3) in slope-intercept form.

Try it yourself

y - 4 = 2(x - 3)

Solve for y

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This lesson includes a short quiz. Start the lesson to answer it and track your progress.

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